Page 232 - Basic Electrical Engineering

Considering currents at node B

I + I = I 4
2
5
or, I + I − I = 0
2
4
5
Substituting

or,

15V − 26V − 15 = 0 (iii)
B
A

Solving (ii) and (iii)
V = 9.38 V
A

Current through the 8 Ω resistor is I and
3

Example 2.49 Use nodal analysis to determine the current flowing through

the various branches in the circuit shown in Fig. 2.158. All resistances shown
are in Ohms.