Page 329 - Basic Electrical Engineering
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Figure 3.30 Phasor diagrams of parallel circuit shown in Fig. 3.29

                  Sum of X component (active component) of branch currents = I  cos ϕ  +
                                                                                               1
                                                                                                       1
               I  cosϕ  + I  cosϕ    3
                2
                             3
                        2
                  Y component of I  (AL) = –I  sin ϕ         1
                                                     1
                                        1
                  Y component of I  (BM) = +I  sin ϕ          2
                                        2
                                                      2
                  Y component of I  (ON) = –I  sin ϕ         3
                                                      3
                                        3
                  Sum of Y component (reactive component) of branch currents = −I  sin ϕ                   1
                                                                                                   1
               + I  sin ϕ  − I  sin ϕ   3
                                3
                   2
                           2
                  Active component of resultant current I = I cos ϕ
                  Reactive component of resultant current I = I sin ϕ

                  Active and reactive components of resultant current must be equal to the
               sum of active and reactive components of branch currents.


                ∴                  I cosϕ = I  cosϕ  + I  cosϕ  + I  cosϕ      3
                                                           2
                                                                  2
                                                                        3
                                              1
                                                      1
                                   I sinϕ = −I  sinϕ  + I  sinϕ  − I  sinϕ     3
                                                                        3
                                               1
                                                            2
                                                                   2
                                                      1
               Resultant current
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