Page 351 - Basic Electrical Engineering
P. 351
Power, P = VI cosϕ = 230 × 10 × 0.5
= 1150 W
Impedance
In complex form,
Z = 23(cos60° + jsin 60°)
= 23 × 0.5 + j23 × 0.866
= 11.5 + j22.99
= R + jX L
Thus, resistance of the circuit, R = 11.5 Ω
Inductive reactance, X = 22.99 Ω
L
or, ωL = 22.99
= 73.21 mH
Example 3.17 A variable resistance R and an inductance L of value 100
mH in series are connected across at 50 Hz supply. Calculate at what value of
R the voltage across the inductor will be half the supply voltage.
Solution:
