Page 372 - Basic Electrical Engineering
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Figure 3.59
Impedance of branch A, Z = R + jX 1
1
A
Impedance of branch B, Z = R + jX 2
2
B
Impedance of branch C, Z = R + jX 3
3
C
Total impedance of the circuit Z is
Total current,
Current, (applying current divider rule)
Current,
By applying the admittance method we can also solve the problem as
Total admittance of the parallel branches B and C
Y = Y + Y C
B
BC
