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j3) Ω, Z  = (10 – j7) Ω and Z  = (6 + j5) Ω. If the voltage applied to the
                                                   C
                         B
               circuit is 200 V at 50 Hz, calculate (a) current I , I , and I ; (b) the power
                                                                            B
                                                                                     C
                                                                        A
               factor for the whole circuit. Draw also the phasor diagram.
               Solution:

















                                                          Figure 3.62

                      Z  = (4 + j3) = 5 ∠36.9° Ω
                      A


                      Z  = (10 − j7) = 12.2 ∠ −35° Ω
                      B

                      Z  = (6 + j5) = 7.8 ∠39.8° Ω
                      C


                      Z  + Z  = 4 + j3 + 10 − j7
                             B
                      A

                                  = 14 − j4


                                  = 14.56∠ − 16°

















                            = 4.19 ∠ 17.9°

                            = 4.19 (cos 17.9° + j sin 17.9°)
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