Page 657 - Basic Electrical Engineering

Induced EMF,

For wave winding, A = 2 = 625 V

E to be the same,

or, N = 750 rpm

Example 7.10 Calculate the output power of a 12-pole separately excited

having 1200 lap-connected conductors each carrying a current if 15 A. The
armature is being driven at 300 rpm. The flux per pole is 60 mWb. Resistance

if armature circuit is 0.1 Ω.

Solution:

Current flowing in each parallel path is the same as current flowing through

each conductor in the path. Since there are 12 parallel paths in the armature
(since A = P = 12), the total armature current is 15 × 12 = 180 A.

Induced EMF,

Power output

Example 7.11 A four-pole, 500 V, wave-wound dc shunt motor has 900
conductors on its armature. Calculate the speed of the motor if its armature