Page 380 - Fiber Optic Communications Fund
P. 380

Performance Analysis                                                               361


           where n and n dQ  are the in-phase and quadrature components of the detector noise. Substituting Eq. (8.195)
                 dI
           in Eq. (8.194), we find
                                   n(t)= n cos ( t +Δ)+ n sin ( t +Δ),             (8.196)
                                                                IF
                                                          Q
                                               IF
                                         I
           where
                                            n = n + n ∕(2RA   ),                           (8.197)
                                             I   cI  dI     LO
                                           n = n cQ  + n ∕(2RA LO ).                       (8.198)
                                            Q
                                                      dQ
           We assume that n(t) is a narrow-band Gaussian noise process with zero mean and it is band-limited to the fre-
           quency interval f − B ≤ |f| ≤ f + B. First consider n cos ( t +Δ). After passing through the matched
                                    IF
                                                             IF
                        IF
                                                       I
           filter, it becomes (see Eq. (8.188))
                 1  T b  n ()s (T +  − t){cos [ (t − T )+Δ]+ cos ( (2 + T − t)+Δ)} d.  (8.199)
                 2 ∫   I   1  b            IF    b              IF     b
                   0
           As before, the second term on the right-hand side can be ignored. So, it becomes
                                           n cos [ (t − T )+Δ],                        (8.200)
                                            FI
                                                   IF
                                                         b
           where
                                            1   T b
                                       n FI  =  2 ∫ 0  n ()s (T +  − t) d.           (8.201)
                                                   I
                                                       1
                                                          b
           Similarly, the second term of Eq. (8.196) becomes
                                           n  sin [ (t − T )+Δ],                       (8.202)
                                            FQ     IF    b
           where
                                            1   T b
                                       n  =       n ()s (T +  − t) d.                (8.203)
                                        FQ  2 ∫ 0  Q   1  b
           Combining Eqs. (8.200) and (8.202), the noise output of the matched filter is
                           n (t)=[n cos ( (t − T )+Δ)+ n FQ  sin ( (t − T )+Δ)],   (8.204)
                                                                        b
                                   FI
                            F
                                                b
                                                                  IF
                                          IF
                                                                                        het
           where n (t) and n FQ (t) are the in-phase and quadrature components of n (t). The PSD of n(t) is N ∕2. From
                                                                    F
                 FI
                                                                                       0
           Eq. (8.7), we have
                                  2     2
                                  = < n >
                                  F     F
                                     N 0 het  1  ∞
                                                      2
                                   =            |H ()| d                               (8.205)
                                       2 2 ∫ −∞  I
                                     N 0 het  ∞
                                                        2
                                                                      2
                                   =         [|̃s ( −  )| + |̃s ( +  )| d].      (8.206)
                                                             1
                                               1
                                                                   IF
                                     16 ∫ −∞
                                                     IF
                                                    ∗
            In Eq. (8.205) we ignore cross-products such as ̃s ( −  )s ( +  ). This is because ̃s ( −  ) and
                                                           IF
                                                                                     1
                                                             1
                                                                                           IF
                                                                    IF
                                                    1
           ∗
           ̃ s ( +  ) represent frequency components centered around  and − , respectively. If the spectral width
                  IF
                                                             IF
                                                                     IF
           1
           of s (t) is smaller than  , these frequency components do not overlap. Noting that the contributions from
              1
                               IF
           the first and second terms on the right-hand side of Eq. (8.206) are the same, we find
                                                                het
                                           N 0 het  ∞          N E 1
                                                                0
                                        2
                                                         2
                                        =        |̃s ()| d =  .                      (8.207)
                                        F   8 ∫ −∞  1          4
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