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Performance Analysis                                                               365


                                   {           [(      Δ  )   ]
                                     2RA LO A cos   −   t +Δ   for 0 < t ≤ T b
                                                   IF
                             I (t)=                    2                                   (8.233)
                              0
                                     0                             otherwise.
           As before, we ignore the scaling factor 2RA LO . The matched filter H () is matched to I (t), j = 0, 1 except
                                                                  Ij
                                                                                  j
           for the phase factor as in Section 8.4.4 (See Fig. 8.18). Suppose s (t) is transmitted so that I(t)= I (t). H ()
                                                                                             Ij
                                                                                        1
                                                              1
           can be realized as correlators and their outputs in the absence of noise can be written as
                                          T b      [(     Δ  )        ]
                               I (t)= A 2  ∫  I () cos   +  ( + T − t) d,          (8.234)
                               1F
                                                      IF
                                            1
                                                                    b
                                         0                 2
                                          T b      [(     Δ  )        ]
                               I (t)= A 2  ∫  I () cos   −  ( + T − t) d.          (8.235)
                                            1
                                                      IF
                               0F
                                                                    b
                                         0                 2
           Eq. (8.234) is similar to Eq. (8.188). Ignoring the frequency component centered around 2 and simplifying
                                                                                  IF
           Eq. (8.234), we obtain
                                                        E 1
                                                 I (t)=   ,                                (8.236)
                                                 1F
                                                        2
                      2
           where E = A T . Similarly, from Eq. (8.235), we obtain
                        b
                 1
                                 A 2  T b  [      (      Δ  )         ]
                           I (t)=  2 ∫ 0  cos Δ +  −  2  (t − T )+Δ d
                           0F
                                                     IF
                                                                  b
                                 A 2  T b
                               =        [cos (Δ) cos (t)− sin (Δ) sin (t)] d
                                  2 ∫ 0
                                    [    (    )]          [    (    )    ]
                                 A 2  sin ΔT b           cos ΔT b  − 1
                               =                 cos (t)−               sin (t),       (8.237)
                                  2      Δ                    Δ
           where
                                             (         )
                                                    Δ
                                        (t)=  −     (t − T )+Δ.                      (8.238)
                                                IF           b
                                                    2
           If
                                         2ΔfT = 2n,  n = 1, 2, … ,
                                              b
                                                  n
                                             Δf =   ,                                      (8.239)
                                                  T b
           from Eq. (8.237) we find that I (t)= 0. The signals are orthogonal for asynchronous detection if the output
                                   0F
           of the filter H () is zero when s , k ≠ j is transmitted. Comparing Eqs. (8.178) and (8.239), we find that
                      Ij              k
           the minimum frequency difference to achieve orthogonality for asynchronous detection is twice that for syn-
           chronous detection. In this section, we assume that Δf = 1∕T so that the output of the filter H () is zero
                                                            b                          I0
           (ignoring noise) when s (t) is transmitted. In this case, the outputs of the envelope detectors can be written as
                             1
                                            √
                                              [           ] 2
                                               E 1
                                     r (T )=      + n  (T )  + n 2  (T ),                  (8.240)
                                      1  b           1FI  b     1FQ  b
                                                2
                                            √
                                     r (T )=  n 2 0FI (T )+ n 2 0FQ (T ),                  (8.241)
                                        b
                                      0
                                                            b
                                                   b
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