Page 388 - PM Integrated Workbook 2018-19

Chapter 15

Example 2, continued

Subject to:

 In Department A, 8x + 10y ≤ 11,000 hours

 In Department B, 4x + 10y ≤ 9,000 hours

 In Department C, 12x + 6y ≤ 12,000 hours

 Non-negativity constraint: 0 ≤ x, y.by the inequality y ≤ 600.

Sales demand for Product Y is also a constraint, that can be expressed by the
inequality y ≤ 600.

Example 2, continued

To draw Constraint 1 (constraint in Department A), we take the inequality

'8x + 10y ≤ 11,000 hours'

and turn it into an equation: 8x + 10y = 11,000. To draw this constraint, we
need two points.

 If X = 0, Y = 11,000 ÷ 10 so Y = 1,100

Likewise, if Y = 0, X = 11,000 ÷ 8 so X = 1,375

 For Department B, if X =0, Y = 900 and if Y = 0, X = 2,250

 For Department C, if X =0, Y = 2,000 and if Y = 0, X = 1,000

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