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(a) Abate            (b) Keen
         (c) Enhance          (d) Alleviate
        95. Haggle
         (a) Zestful          (b) Concur             98. Doctor, Engineer, Person
         (c) Quibble          (d) Foster
        96. Deceitful
         (a) Deceptive        (b) Valid
         (c) Squalor          (d) Trivial            99. Grams, Beans, Legumes
        Directions (Q. No.97-100): Each of these questions
        given  below  contains  three  elements.  These
        elements may or may not have some inter-linkage.
        Each  group of  elements  may  fit  into one of  these   100. Criminals, Thieves, Lawyers
        diagrams at (a), (b), (c) or (d). You have to indicate
        the group of elements which correctly fits into the
        diagrams.

        97.  Parents, Friends, Uncles


                                           Hints & Solutions
        1. Sol: (b)                                  Then the length of the train is,
        If we assume no. of student=100              ∴     =  25  ×  36  =  900    . . . . . (1)
                                                                                           5
        Number of boys=60                            Speed of the second train = 45       =  45  × ( ) =
        And number of girls=40                       25                        ℎ          18
        Given that 20% of boys and 25% of girls are getting   2     /      .
        scholarship.                                 Length of the second train is 100 m shorter than the
        So, 20% of 60 =12                            first train.
        And 25% of 40 =10                            So, length of the second train is = 900 – 100 = 800m
        So, total number of students who are scholarship   Time  taken  to  cover  the  tunnel  by  second  train  =
                                                           2
        holders = 12+10= 22.                         800 ×  25  =  64       
        2. Sol: (a)                                  4. Sol: (a)
        Ratio of times taken by A and B = 1 : 3      (A + B)'s 1 day work =  1  . . . (  )
        The time difference is (3 - 1) 2 days, while B take 3           12
                                                                        1
        days and A takes 1 day.                      (B + C)'s 1 day work =  15 . . . (    )
        If the difference of time is 2 days, B takes 3 days.   (A + C)'s 1 day work =  1  . . . (      )
        If the difference of time is 40 days, B takes    Adding (i), (ii) and (iii)   20
         3
        ( × 40) = 60 days                            (   +   ) + (   +   ) + (   +   ) = (  1  +  1  +  1  )
         2                                                                        12  15  20
        So, A takes 20 days to do the work.          2(   +    +   ) =  12
                       1
        A's 1 day's work =                                          60
                                                                    1
                       20                            2(   +    +   ) =
                       1
        B's 1 day's work =                                       1  5
                       60                               +    +    =
        (A + B)'s 1 day's work = (  1  +  1  ) =  4  =  1        10
                                                                               1
                            20  60   60  15          Hence, (A+B+C)’s 1 day work =
        Therefore, A and B together can do the work in                         10
        15 days                                      So, it will take 10 days for them to do the work
        3. Sol: (d)                                  together.
        Speed of the first train = 90     /ℎ   =  90  ×  5. Sol: (c)
          5                                          Required number=  53  × 100= 353.33 ≈ 353
         ( )    /        =  25   /                                    40−25
         18
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