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6. Sol: (c)                                  10. Sol: (b)
        (Tuesday + Wednesday + Thursday)/3=38        Speed of the train = 6km/s
        Tuesday + Wednesday + Thursday= 114 ...(1)   Train takes 18s to cross a man
        (Wednesday + Thursday + Friday)/3=37         Length of the train = 6 × 18 = 108m
        (Wednesday + Thursday + Friday) =111 ...(2)   Time  takes  to  cross  a  person  running  at  9km/s  =
        Given Friday is 39.                          108/9 = 12s
        Then, (1) - (2) => Tuesday - Friday = 114-111=3   11. Sol: (d)
        So, Tuesday – 39 = 3                         Length of the platform = 150m
        Tuesday = 3+39 = 42 degree.                  Length of the train =   
        7. Sol: (a)                                  (150 +   ) covered in 22s.
        Let the cost price be x and y.               Speed of the train, =  150  = 15  /  
           +    =  560  … . (  )                                       10  150 +   
            =  560 –                                                 15 =
                              115                                           22
        Selling price of one watch=     (sold at 15% gain)          150  +      =  330
                               100
        Selling price of another watch=  90     (sold at 10%        =  330 − 150  =  180  
                                  100                Therefore the length of the train is 180m.
        loss)
        115    +  90(560−  )   = 560                 12. Sol: (c)
        100     100                                  Let   = tank capacity
        115  +50400−90    = 560                      1         3
            100                                      5      + 22 =   
                                                               4
        25x = 56000 – 50400                          22  =  11   
        25x = 5600                                         20
                                                         =  40 litres.
        x = 224
                                                     13. Sol: (a)
        y = 560 – 224 = 336                                                     1  1 1  1
        Cost price of the watches are Rs.224 and Rs.336.   The ratio among A, B, C and D = ∶ : ∶
                                                                                3
                                                                                       6
                                                                                   4 5
                                                                                 :
        8. Sol: (b)                                  On rearranging the ratio =  60  ∶  60 60  ∶  60
                                                                            3  4  5   6
        Suppose, A’s total income is Rs.                            = 20: 15: 12: 10
        A spends 1/3 of his income on rent.          So number of pens can be minimum when the
                      1    2
        Remaining =    −    =                        common ratio is 1.
                      3    3
        From remaining he spend 1/4 on food 1/5 on movie.   So minimum number of pen = 20+ 15 + 12 + 10=57
        So, money spent on food and movie            14. Sol: (d)
             2
                  1
          1
                      2
                          1
         =          +         =     +  2             Speed = Distance/Time
          4  3    5   3   6   15                     75  = 4.16   /  
        =  5  +4    =  9    =  3                     18
           30    30  10                              75  = 3.41   /  
                                     1
        Remaining money in salary =    − ( +  3  )      22
                                     3  10           Average speed of the train =  4.16+3.41
              19
        =    − ( )   =  30−19  =  11                    7.57                    2
            11   30   30    30                       =   2  = 3.785   /  
        Now,    =  1760
             30                                      15. Sol: (c)
        ⇒     = 4800                                 Let the principle amount be Rs.P.
        Hence, A’s total income is Rs.4800           Number of years = 4
        9. Sol: (a)                                  Let the rate of interest be x%.
        Let the numbers be 12   and 13                    =          =    ×4×  
                       12   − 20  2                       100    100
                                =                    If he had lent for 2% more he would have earned
                       13   − 20  3
                ⇒ 3(12   − 20) = 2(13   − 20)        more Rs.56
                          ⇒    = 2                   ⇒    ×4×(  +2)  −    ×4×    = 56
                                                          100
        Hence, the numbers are 24 & 26                  4    +8    4      100
                                                     ⇒       −     = 56
                                                         100   100
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