Page 355 - Services Selection Board (SSB) Interviews

Cubes and Dices 351

Answer with Explanation

Solutions Of Cubes and Dices

1. There is 6 columns with 2 cubes each. Total boxes = 6. One column with 10 boxes = 1 × 10 = 10
6 × 2 = 12, option (c)
Two column with 7 boxes = 2 × 7 = 14
2. There are total 4 rows and 5 boxes in each row, then One column with 4 boxes= 1 × 4 = 4
5 × 4 = 20 boxes. Option (a)
Total boxes = 28, hence option (c)
3. There are total 42 cubes present in the upper portion.
Then total cubes be 42 × 2 = 84 7. Total cubes = 9
or 8. There are 9 columns with 5 cubes = 9 × 5

24 columns with 2 cubes each = 24 × 2 = 48 There are 7 columns with 4 cubes = 7 × 4
14 columns with 2 cubes each = 28 There are 5 columns with 3 cubes = 5 × 3

4 columns with 2 cubes each = 8 There are 3 columns with 2 cubes = 3 × 2
Total cubes = 48 + 28 + 8 = 84, hence option (a) There is one column with 1 cubes = 1 × 1
4. 4 columns with 1 cubes = 4 cubes Total = 9 × 5 + 7 × 4 + 5 × 3 + 3 × 2 + 1 × 1 = 81

1 columns with 3 cubes = 3 [ note you have observed that the particular figure
1 columns with 4 cubes = 4 where the number of column decreases by 2 and
number of cubes by 1 ]
Total cubes = 4 + 3 + 4 = 11, option (b)
9. Option (d), i.e 15 × 3 + 13 × 2 + 11 × 1 = 82 cubes
5. Total cubes 25, option (b)
10. Option (c) there are 20 cubes.

Dice – concept applicator

1. Option (d) From both the figures we find that respectively. Clearly by combination, 3 dots lie on
numbers 1,2,3 and 4 dots appear adjacent to 6 . the face opposite the face having 2 dots. Therefore,
thus, the number 5 dots will appear opposite to 6. when there are 2 dots at the bottom, the number of
Therefore when 6 is at the bottom, then 5 will be at dots at the top will be 3.
the top.
4. Option (c) as we can observe the position of 6 is
2. Option (c) Number three is common in both the same in both the figures and position of 4 moves
figures we assume the block in figure (ii) to be rotated from Right hand side to Left hand side (clock wise
so that three appears at the same position as in direction). Clearly we can observe that 5 is just
figure (i) and the numbers 5 and 2 move to the faces opposite of number 1.
hidden behind the numbers 4 and 6 respectively. 5. Option (c) as number 6 position is same in both the
Thus the combined figure will have 3 on right hand figures. We can assume that the dice to be rotated
side face, 4 on the front face, 6 on the top face, 5 on so that 6 remains on the same face and 1,3,4 and 5
the rear face and 2 on the bottom face. Clearly when will be arranged ascending order as all are adjacent
2 is at the bottom, then 6 is at the top. to 6. Hence, when 3 is in top, 5 will be at bottam.
3. Option (a) Number 1 is common to both the figures 6. Option (c) as 5 is common on both the figure, and
(i) and (ii). The dice in fig. (ii) is assumed to be 1,2,4 and 6 are adjacent to 5 . hence 3 is opposite
rotated so that 1 dot moves to the top face i.eto of 5.
the same position as in figure (i) and 2 and 4 dots
move to the face behind the faces with 3 and 5 dots