Page 190 - FISIKA SMA KELAS X

LAMPIRAN

KUNCI JAWABAN

BAB 1 5. r r
a . b = a . b cos α
8
A. 4 0 = 0 cos α
α =0 6 o
1. C r r
3. D | a . b|= a . b sin α
2
2
F 2 = F + F + 2F F cos α = 10 . 8 . 1 3
R 1 2 1 2
2
1200 = 3F 2 2
= 40 3 N
F = 20 N
5. A
r r BAB 2
|a . b|= a . b sin α
A.
1 o
= bb sin 30
.
4 1. B
= , 0 125 b 2 S = 5 x 36 = 180 m
r
7. C s = 0
S . u = 3,5 m 3. B
S . P = 0,20 mm 5. C
+
H.U = 3,70 mm 1
S = . 4 . 20 = 40 m
9. B 2
20 − 0
a = =5 m 2
B. 4 s
7. D
1. a. Karena perpindahan adalah perubah-
an posisi 9. C
b. Tidak sama Syarat benda seimbang ΣF = 0
c. Jarak, panjang lintasan yang ditempuh 11. B
perpindahan, dan perubahan posisi a ~ α
3. a. F = F + F = 35 N a ~ ⁄ 1
Rmaks 1 2 m
b. F = F – F = 5 N 13. E
Rmin 1 2
c. 2 2 15. C
F = F 1 + F 1 + F F cos α
R
12
h A = h B
F = 400 225 300+ +
R 1 2 1 2
t
t
F = 0,41 N V oA A − gt A = V oB B − gt B
3
R 2 2
2 2
F 2 = F R 20( t B + 2) − 5( t B + 2) = 50 t B − t 5 B
sin β sin α 20 = t B
t B = 04, sekon
, 1 5 30 ,41
=
sin β sin 0 6 o B.
sin β 0
= ,4272
1. v = v – v
o
sin β 2 PQ P Q
=5,29
50 = V – 70
P
V = 120 m/s
P
Fisika SMA Kelas X 183