Page 191 - FISIKA SMA KELAS X
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3.  Gerakan dari A ke B
                                                            b.              1   2
                     v = v + at                                 h 2  =  v o  −  t +  gt 2
                                                                         2
                      t  o   1                                        2     2
                     40 = 0 + 2t 1                              h 2  =  1000 −  500
                     t = 20 sekon                               h  = 500 m
                      1                                          2
                              1⁄
                                 2
                     S AB  = v t +  at = 400 m                  h=h 1  +  h 2  =  1500 m
                               2
                          o 1
                                1
                                                                            .
                     S  = S  – S  = 200 m                       v  =  2 gh =  30 000
                      BC  AC  AB                                 t
                                                                v
                     Gerakan dari B ke C                         t  =  173 2 m/s,
                     S BC  = V . t 2                    BAB 3
                          2
                     200 = 40 . t
                             2
                                                        A.
                     t = 5 sekon
                      2
                     t = t +t = 25 sekon                1.  A
                        1  2
                                                        3.  B
                  5.
                                                            1  1   1
                                                              +  =
                                                            s  s'  f
                                                             1  1   1
                                                              −   =
                                                            ∞   50  f
                                                            f =− 50 cm

                                                               100
                            2                               p =   = − 2D
                          mv
                      F =                                       f
                      s
                           R                            5.  D
                               2
                             mv                             f  < s  < 2f
                      N −  W =                              ob  ob  ob
                              R                         7.  A
                                    2
                               ,
                              002 .  v                      s ok  < f ok
                      06  − 0 2,  =
                       ,
                                02                      9.  B
                                 ,
                           ,
                       2  008
                      v  =    = 4
                           ,
                          002                           B.
                       v = 2 m/s                        1.
                                                            1  1  1
                  7.  ΣF = m . a                              +  =
                                                            s  s'  f
                     F + F cos α = m . a                     1  1   1
                         2
                      1
                                                               ±  =
                     2 + 0,5 = 2a
                                                            25  50  f
                     a = 1,25 m/s 2                         f =  50 cm

                             1  2                              100
                      S =  v t +  at                        p =   =  2D
                          o
                             2                                  f
                           1
                      S =+    . 1,25 . 100              3.
                         0
                           2                                   100  100
                                                            f =   =      cm
                      S = 62,5 m
                                                                p   20 5 ,
                  9.  a.  v  2  = v  2  + 2ah               1  1  1
                         t 1  o    1                          +  =
                         v  2  = 6400 + 3600                s  s'  f
                         t 1                                1  1  20 5 ,
                         v = 100 m/s                          +  =
                         t 1                                s  5   100
                         v = v      v    v                  1  0 5 ,
                         t 2  o – gt ⇒  o =   t 1             =
                                 2
                              2
                                      2
                         0 = 100 = 10t                      s  100
                                  2
                                                              s = 200 cm
                         t = 10 sekon
                         2
                  184                                                             Kunci Jawaban
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