Page 25 - The 40 Ch. Book by James Hong or 洪祥智

m = mass mass v= velocity speed E= energy energy t=time =
time
x= distance distance k = elastic coefficient angle = angle r=

radius = radius

Derive a Derivation 1: 1/2 mv^2 = E ;; v = (2E/m)^(1/2) = x/
time;; Time= x/ (2E/m)^1/2;; Time = (x^2/(2(1/2kx^2))^1/2

xm^1/2 = (m/k)^1/2;; If v=r angle/ time, x = r (2 Pi);; t= time =
2 pi (m/k)^1/2; Note:: angle= 2pi is a random hypothesis. Right

in math but wrong in physics 1/2mv^2= 1/2 kx^2 = E does not
apply in pendulum swing.

Derivation 2 Derivation 2: Another way 1/2mv^2 = E = 1/2
kx^2 ;; mv^2= kx^2;; mx^2/t^2 = kx^2 ;; m/t^2 = k;; t = time =

(m/k) ^1/2;;; If v=r angle/ time x = r (2 pi);; t= time = 2 pi
(m/k)^1/ 2;; Note:: angle= 2pi is a random hypothesis. Right in

math but wrong in physics 1/2mv^2= 1/2 kx^2 = E does not
apply in pendulum swing.

The single pendulum period derivation is based on energy = 1/2
mv^2 (kinetic energy) = 1/2 kx^2 (spring kinetic energy), but

the pendulum motion and linear motion are different. So the
formula does not hold and the deduction is incorrect. In

addition, the angle of the pendulum is not necessarily a full
circle (2 pi), so (2 Pi) is said incorrect.

The pendulum period formula, (which I wrote) should be – Time
= C1(L(initial angle)/mg). The simple pendulum period formula

should be the constant multiplied by (single pendulum line
length) multiplied by (starting pendulum angle) divided by

(mass) divided by (gravity acceleration).

6.3 Is the black hole a solution to general relativity?