Page 12 - E MODUL MTK PEMINATAN (FUNGSI EKSPONEN DAN LOGARITMA)

3. (2 ) = …
3 4
Jawab:
(2 ) = (2 ) × ( . . . ) × (2 ) × ( . . . )
. . .
3
. . .
3 4
3

= (2 × 2 × 2 )×(...×...×...)×(...×...×...)×(...×...×...)
3
3
3
= (...×...×...×...×...×...×...×...×...×...×...×...)
= 2 ...
= 2 …×…

( ) = …×…

4. (3 ×5) = . . .
3
Jawab:

(3 ×5) = (...×...) ×(...×...) ×(...×...)
3

= (3 ×...×...) × (5 ×... × ...)

...
...
= ... ×...

( × ) = ×

...
...

4
3
5. ( ) = …
7
Jawab:
4
3 3 … … …
( ) = ( ) × ( ) × ( ) × ( )
7 7
… … …

… ×… ×… ×…
= ( )
… ×… ×… ×…
….
= ( …. )
…. ….

… . ….
( ) =
… . ….

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