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04Numbers in Disguise Unit

2 . Write the missing numbers in the blanks to solve the puzzle. 2. Have the students solve the puzzle by filling
in the values that belong in each blank.
Since A + A = 6, a.
6 can be made by AA 2a. Have the students fill in each blank after
A reading the description given by the character.
3+3=6 B6 Students should be able to complete this
or 8 + 8 = 16. activity individually.
A can be 3 or 8.

When A = 3, When A = 3 When A = 8
33
the sum of the numbers 3 88
in the ones place is 6. B6 8

B6

When A = 3, B = 3. B= 3 B= 9
() ()
Since A and B are

different numbers,
A 3.

88
8

96

4. Numbers in Disguise 37

Solution:
3-digit number 3-digit number 4-digit number. The digit in the highest place value, B is 1.
C and A cannot be 0 or 1. C A 11, and regroups to make 1 ten. 1 B B 1 1 1 3. C 3.
A 8 which completes the number sentence. 813 318 1,131.

Answer:
813
318

1131
4A Unit 04 057
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