Page 66 - MESINARUSTERUS

= =

Ia2 = 100A
Eb1 = Vt - Ia1Ra = 240 – 50(0.2) = 230V

Eb2 = Vt - Ia2Ra = 240 – 100(0.2) = 220V

= =

N2 = 526.1 psm

Contoh 3.6
Sebuah motor pirau at 6 kutub, 100V mempunyai belitan pengalir angker sebanyak
540 jenis belitan tindih (lap winding). Motor ini mengambil arus sebanyak 15A
daripada bekalan masukkan dan kuasa sebanyak 1.5kk (hp). Belitan medan
mengambil sebanyak 0.5A. Rintanga angker (armature resistance) sebanyak 0.9Ω
dan bilangan flux per kutub sebanyak 20mWb. Kirakan
i. Kelajuan motor ini
ii. Daya kilas aci (keluaran ) dalam newton-meter

Penyelesaia 3.6 I sh I in
I a
Shunt field
winding G dc source

armature

Arus angker (armature current), Ia = Iin - Ish = 15 – 1.5 = 13.5A

Voltan balikan (back emf), Eb = - - V brushes = 100 - 15(0.9) = 86.5V

formula Voltan balikan (back emf), =

kelajuan, N = = = 8.01 pss

Formula Tsh = = = 22.25Nm

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