Page 144 - Dasar Perencanaan Struktur beton bertulang OK 1_Neat

 H = 0

Tf = Cf
Asf.fy = 0,85.fc' b -b .hf
e w
0,85.fc'. b -b .hf
e w
Asf =
fy
Sehingga ,

 hf   hf 
Mnf = Cf. d-  atau Tf. d- 


 2   2 
 hf   hf 
Mnf = 0,85.fc' b -b .hf. d-  atau Asf.fy. d- 


e w
 2   2 

Balok badan (Gb.2)

Luas tulangan tarik pada badan, As = As total -As
w
f
Gaya tekan, C = 0,85.fc'.b .a
w
w
Syarat keseimbangan :
 H = 0
C = T w
w
0,85.fc'.b .a = As .fy
w
w
As .fy
w
a =
0,85.fc'.b w
Sehingga,

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