Page 461 - SUBSEC October 2017_Neat
P. 461

02212020/CAPE/SPEC/MS/2017
                                                          - 3 –

                                                       CHEMISTRY
                                                   UNIT 2 — PAPER 02
                                                      MARK SCHEME
                                                                                                KC     UK   XS
              (e)  (i)       Colourless gas evolves (1) which forms dense white fumes
                             with NH3  (1)                                                    [2 marks]
                     (ii)    COOH/Carboxylic acid group present                  [1 mark]
                                                                                                             5
                    (iii)    Dil. HCl is added and the resulting solution heated
                             gently                                                            [1 mark]
                     (iv)    The NH2 and amine group present                       [1 mark]


              (f)           They show a steady gradation in physical properties
                            Chemical properties are similar
                                                                                                 3
                            Relative molecular mass of consecutive members increase
                             by H or CH2                               [1 mark each]


                                            
                                       
                                           
              (g)  (i)  Cl – Cl       uv / sumlight   2 Cl                      [1 mark]
                                         
                                                      
                           Cl + CH3CHCH3CH3  CH3  C CH3CH3 + HCl                 [1 mark]
                                                                                                      5
                           Cl + CH3CHCH3CH3  C H2CHCH3CH3 + HCl                  [1 mark]

                                          
                          CH3 C CH3CH3 + C l  CH3CClCH3CH3                       [1 mark]
                                            
                          CH2CHCH3CH3 + C l  CH2ClCHCH3CH3                       [1 mark]
                          (propagation steps also acceptable)

                    (ii)  CH3CClCH3CH3
                           Stability of  the  tertiary free radical in the                             2
                           intermediate stage                            [2 marks]

                       For 2 – methylpropene, the mechanism is  electrophilic
              (h)
                       addition (1). The double bond causes   polarization of the

                       Chlorine molecule which produces  the  electrophile by
                       heterolytic fission (1). The mechanism for the 2-methyl
                       propane is free radical substitution  (1)  involving                            4
                       homolytic fission. (1)               [4 marks]



























                                                                             Total 30 marks     10     15    5
   456   457   458   459   460   461   462   463   464   465   466