Page 13 - MODUL BILANGAN BERPANGKAT

PEMBAHASAN LEMBAR KERJA SISWA

3
-2
6
5
1. 7 x 7 x 7 = 7 3+5+(-2) = 7
1
- 3
- 4
-1
2. 3 : 3 = 3 -4 – (-3) = 3 =
3
−1
1
2
2
2
−2 −1
2
3. 5 ( ) : 5 = 5 (5 ) : 5
25
2
2
2
= 5 x 5 : 5 = 5 2+2-2 = 25
.3 )
3
4. (2 −1 2 2 = 2 −2 4
4 2
2
(2 .3) 2 2 3
3
= 2 −2−4 4−2
1
9
−6
2
= 2 . 3 = x 9 =
2 6 64
1 1 2 1 1 2

6
3
4
5. 81 4 + 64 6 - 27 3 = (3 )4 + (2 )6 − (3 )3
= 3 + 2 – 9 = -4
1
6. Jika x = , y = 16 dan z = 27 maka :
4
1 1 1 1 − 1 1 1
−
2 − 4 + 3 = ( ) 2 − 16 4 + 27 3
4
1
− 1 1
1 2
3
4
= ( ) - (2 )4 + (3 )3
2 2
1
−2 −
= (2 ) 2 – 2 + 3
= 2 – 2 + 3 = 3
1 3 1 1 3 1

2
5
2
7. 16 2 . 32 5 . 36 2 = (4 )2 . (2 )5 . (6 )2
= 4 x 8 x 6 = 192
−3 2 2 2 −6 4 4

−2 6 −4
8. ( ) = = −6−(−4) 4−(−2) 4−8 =

−2 −1 4 −4 −2 8

9. Semua langkahnya valid

10. Semua langkahnya valid