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                                                                        h    R
                                                                        ∆


                                                                          ≈

                                                      α                   α

                                                    2                     sin              h   R
                                                      cos                                  ∆                  Prof. Ramesh Singh, Notes by Dr.   Singh/ Dr. Colton


                                                      1−                                     ≈  h


                                       h    R                     0                        h  ∆  ∆  −
                                       ∆    2         =              2                         R
                                         1−           α                     
                                         =                             ∆h    2R              ≅

                                   h    2             sin                                  2      
                                   ∆                                      −                     h    R
                                     −      R                          ∆h    2R                 ∆    2
                                     R                                                 h   R        
                                          =                               1+           ∆        h  +  R
                                         cosα        R                    1−                    ∆  −  1



                                                     <<                   =                  =


                                 Also              and  h  ∆              sinα               tanα
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