Page 215 - Chemistry
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Usefull heat  = 75X150  = 112.5 kj
                                                     100
                            Let volume of water             = V
                                                                o
                            Room temperature                = 25 C
                                                                  o
                            Boiling point                   = 100 C
                                                                         o
                             Change in temperature, T     = 100-25  = 75 C   ½ mk
                            T X mass X C                      Q      315V = 112500
                             75 X V X 4.2                =112.5     V = 112500       ½ mk
                                  1000                               1                        315
                                                        3
                                                                    V = 357.km      ½ mk

          32.               RFM  Na 2CO 3  = 43 + 12 + 48  = 106
                     Mol. Na 2 CO 3  = 19.6   = 0.8149057
                                                  106
                     Molarity of Na 2 Co 3   = 0.1849057   = 0.73962m
                                                                  0.25
                  Na 2 Co 3(aq) + Mg Cl 2(aq)  + MgCo 3(s)
                 Mole ratio Na CO 3 : Mg Cl 2 is  1:1
                  mol. Mg Cl 2 Reacted =  0.1849
                 If 2.0 mol.           = 1000cm3 solution mg cl 2
                 = 0.1849mol           = 0.1849 X 1000
                                                     2
                                                         3
                                                     = 92.45 or 92.5 cm

          33.    i)     ACID                                BASE
                           1                                   2
                                                                3
                        ½  0.004                              20cm   X 0.2 moles
                                                                   3
                               = 0.002 moles   ½                1000cm                  = 0.004 moles

                             3
                        25cm  ________ 0.002 moles   ½
                                3
                         1000cm  ______ ?
                                                     3
                                              1000cm   X 0.002 moles = 0.08 M  ½

                 ii) 0.08 moles ________________ 10.08 g H 2C 2O 4xH 2O   ½
                     1 mole __________________              ?

                                          1 mole     X 10.08       = 126   ½
                                          0.08 moles
                                      126 _______ H 2C 2O 4xH 2O

                                              18x = 126 – 90   ½
                                              18x = 36
                                                  X = 2       ½

          34.    Mg  (g)   + 2HCL  (aq) ___________ MgCl 2 (aq)    + H 2 (g)
                                                                     3
                 24g _________________________________ 22.4dm
                 16g _____________________________________?

                                                                 3
                                             3
                               1.6 gx 22.4dm     ½  = 1.4933 dm



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