Page 247 - Chemistry
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II  a)(i) Curve I    Reason:  F increases as E decreases.

                   (ii) Equilibrium is achieved.

          8.      Q = 40000 x 60 x 60 = 144000000c
                     Mass of Al = 144000000 x 27   1
                                                3 x 96500
                                          = 13.43kg    1

          9.     a) Hydrochloric acid is a weaker oxidizing agent which cannot oxidize copper to form
                          Nitrogen  (VI) Oxide gas
                 b) It increases    1 mark
                        Molecules/ particles acquire the necessary activation energy// Kinetic energy. This
                                  increases the frequency of collisions hence the rate of reaction  ½  mark
                 c) Graph      - Scale 1 mark with axis well labeled
                               - Plotting + all points correct            1 mark
                                                 5 correct points     ½ mark
                                          Less than 5 points       0 mark
                                         Correct smooth curve      1 mark
                                                              TOTAL 3 marks

                                 3
                 d)     i) 360cm  Read correct value from graph + .05
                                                                    -
                                3
                        ii) 40cm  = Value from graph + .05
                                                             -
                                 Read where it levels off

          10.    (a) 260 – 85 = 175 = 87.5cm 3/mn;
                             2           2
                 (b) 4 ½ min;
                 (c) Zinc was used up / H 2SO4 used up;

          11.    (a) Platinum / Platinum Rhodium
                  (b) Pressure -9atm   (  ½ mk)
                               o
                                       o
                         Temp – 700 C – 900 C    ( ½ mk)
                    (c) Reaction is exothermic

          12. (a) (i) Will increase;
                     (ii) Decrease;
          13.
               Dissolve solid √  ½  YSO 4 to obtain √  ½  YSO 4 in solution,
               Dissolve  √  ½  X(NO 3) 2 in water to obtain  √  ½  X (NO 3) 2 solution.            3
               Mix the two above solutions
               Filter to obtain XSO 4 solid residue, rinse with water and dry by heating √  ½
               under asbestos  pad.

          14.    R (s)    + S 2+ (aq)                         R 2+ (aq)   +   S (s)   √1  (1 mk)
                 E.m.f  = 0.47 – (-2.04)
                        = -0.47 + 2.04                                                    2
                        = 1.57V √1                                 (1 mk)


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