Page 350 - GMAT 2017b_Neatb

Computer Literacy Test 1

(C) A B C 87. Reduce X Y Z + X Y Z + X Y Z + X Y Z
(D) A (B + C) (A) Z
(B) Z Z
80. Boolean expression for the truth table given below will (C) Z
be (D) 0
(A) CBA + CBA = y
(B) CBA + CBA = y 88. AB + AC + ABC (AB + C) is reduced to
(C) CBA + CBA = y (A) 0
(D) CBA + CBA = y (B) A
(C) B
C B A y (D) 1
0 0 0 0
0 0 1 0 89. De Morgan’s law states that
0 1 0 0 (X + Y)¢ is equal to
0 1 1 0 (A) X¢ + Y¢
1 0 0 0 (B) X¢ Y¢
1 0 1 1
(C) XY + X¢ Y¢
1 1 0 1
(D) None of the above
1 1 1 0
90. X + X¢Y is equal to
81. The binary number 101100.1100 in octal number will
be (A) X + Y
(A) 152.6 (B) XY
(B) 154.6 (C) XY
(C) 145.6 (D) 1
(D) 174.6
91. (X + Y) (X + Z) is equal to
(A) X + XY
82. In decimal system base or radix is
(A) 1 (B) X + XZ
(B) 2 (C) X + Y
(C) 10 (D) X + Z
(D) 16
92. Dual of XY + XY¢ + X¢Y is equal to
83. On 8241 Binary Code Decimal System, the decimal (A) (X + Y) + (X + Y¢) + X¢Y)
number 237 is represented by : (B) (XY) (XY¢) (X¢Y)
(A) 1000110111 (C) (X + Y) (X + Y¢) (X¢ + Y)
(B) 100011110 (D) None of the above
(C) 001000110111
(D) 10010010011 93. Dual of X + Y¢ is
(A) 0
84. Read and write capabilities are available in (B) 1
(A) RAM (C) XY¢
(B) ROM (D) Both (A) and (B)
(C) Both Ram and Rom
(D) Neither Ram nor Rom 94. Which of the following is incorrect?
(A) A + A¢ = 1
85. Which mode is the extracting information storage? (B) A + 0 = A
(A) Read mode (C) A.1 = A
(B) Write mode (D) AA¢ = 1
(C) Read and write mode
(D) Neither read nor write mode
95. Which of the following is incorrect?
(A) (A + B)¢ = A¢ + B
86. Most of the digital computer do not have floating point
hardware because (B) (AB)¢ = A¢ B¢
(A) Floating point hardware is costly (C) A(A + B) = A
(B) It is slower than software (D) (X + YZ) = (X + Y)(Y + Z)
(C) It is not possible to perform floating point addition
by hardware.
(D) Of no specific reason

353