2 1 − ( ) () = 2 2 2 [ {1 − ( ) } + (2/ ) ] and −2/ () = 2 2 2 [ {1 − ( ) } + (2/ ) ] The total displacement lag behind the force vector is given by, 2/ = tan −1 [ 2 ] 1 − ( ) The steady state solution becomes, 1 = (−) 2 2 √ {1 − ( ) } + (2/ ) 2 3