Page 21 - contoh LKPD flip

Jawab :
+
-
HCL → H + Cl
+
[H ] = x . [HA]
= 1 x 0.01 M
-2
= 10 M
-2
pH = - log 10
pH = 2

2. Berapa pH dari :
a. Larutan HCL 0,1 M

b. Larutan H 2SO 4 0,001 M

Jawab
+
-
+
2-
a. HCL → H + Cl b. H 2SO 4 → 2 H + SO 4
+
+
[H ] = x . [HA] [H ] = x . [HA]
-3
= 1 . 0,1 = 0,1 M = 2 . 0,001 = 2 x 10 M
-3
-1
pH = - log 0,1 = - log 10 pH = - log 2 x 10
= 1 = 3 – log 2
3. Hitung pH larutan dari 2 liter larutan 0.1 mol asam sulfat!
Jawab :
Molaritas = mol/v = 0,1 / 2 = 0.05 M

+
2-
H 2SO 4→ 2 H + SO 4

+
[H ] = x . [HA]
= 2 . 0.05
-1
= 0,1 = 10 M
-1
pH = - log 10
= 1

b. Asam lemah

Untuk SMA Kelas XI / Semester 2| ASAM BASA 21