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MORE COMPLICATED ELEMENTS OF FEED LINES                                 421



            8.4.4   K - and J - Immittance Inverters
            Looking back at Table 7.1 and 7.2 in Chapter 7 and Section 8.1 of this chapter, we see that a
            plenty of different discontinuities and components in feed line can be used as building elements
            of filters shown in Figure 8.4.1. One of such coaxial filter realization was demonstrated in
            Figure 7.3.4. According to this drawing, we have used two different types of discontinuities,
            one series and another shunt, that  might seriously complicate filter implementation. It is
            preferable to have either all  shunt  or all series elements.  Sometimes, such straight filter
            implementation is prohibited by extremely high impedance variations from element to element
            that makes their practical realization questionable or just impossible. The effective way to go
            around is to use so-called K- or J-inverters [8, 10] depicted in Figure 8.4.4 at some central
            frequency  .
                      ′














               Figure 8.4.4  Inventors’ equivalent circuits: a) and b) K-invertors, c) and d) J-invertors.

            After some algebra, we readily obtained the input impedance   of K- and the admittance   of
                                                                                    
                                                              
            J-invertors
                                                         2
                                          2
                                        =  /  ,        =  /             (8.9)
                                                     
                                     
            Here      and      is the output load and admittance, respectively. For example, let  us
            demonstrate how J-inverter works considering the resonance circuit shown in Figure 8.4.5a.
            According to (8.9) the input admittance of the first J-invertor on the right side coupled to the
            admittance    is equal to   / . Collecting this admittance and the admittances of shunt
                                   2
                                     0
                      0
            resonance circuit,  we could find the total load connected  to the left side invertor as  =
                                                                                    Σ
              /  +  + 1 ℒ . Finally, according to (8.9) the input  impedance  of the second
             2
                           ⁄
                0
                       1
                                1
            invertor on the left side is
                        = 1/( /  ) =   + 1 ℒ  + 1   =  ℒ ̂ + 1  ̂ +         (8.10)
                                                    2
                                         2
                            2
                                       ⁄
                                                                      ⁄
                                              ⁄
                                                        ⁄
                               Σ       1          1        0                  0
             Figure 8.4.5  J-invertors connected to shunt circuits: a) Block diagram, b) Equivalent circuit,
                                c) Band-pass filter using shunt circuit only.
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