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MORE COMPLICATED ELEMENTS OF FEED LINES                                 435




                                  1        +1  1  1       +1
                         
                       � � =  �  / +1  �  11 � �  � =  �  11 � �  �    (8.17)
                                                         
                             2     1   +1  1+ 11     1   +1
                             �1−|
                                 11  |  11                   11
            The next step is to take into consideration that the output incident  +1  and reflected  +1  waves
            should be  defined on (i+1)-interface, i.e. shifting the reference plane for them as   +1  →
             +1     and  +1  →  +1   −     where  =   . Therefore, the scattering transfer matrix 
                                                  
                                             
                                                                                       
            relating waves on i- and (i+1)-interface can be written in the form
                                                       
                                         1             − 
                                                       11
                                    =   �                �                        (8.18)
                                         
                                        1+ 11       − 
                                              11
                                                                   +1  = −  . If so,
                                                                           
            On the next (i+1)-boundary where  +2  >  +1  we evidently have   11  11
                                                           
                                          1         −  − 
                                                          11
                                      =  �                   �                     (8.19)
                                   +1    
                                        1− 11 −        − 
                                                11
            According to (7.23), the product of these two matrices is the transfer matrix of single bilayer,
            i.e.    =    . As soon as the dielectric stack is formed by N identical bilayers, its transfer
                       +1
            matrix yields  = ( )  where ( )  is the matrix product of N copies of  . Completing
                               
                                            
                             
                                         
                                                                           
            all multiplications analytically or numerically, we could obtain the transparency characteristics
                                                                     ⁄
            of multilayer thin-film stack analyzing the matrix component  22  = 1   in the frequency
                                                                       21
            domain (look back at expression (7.19)). However, more urgent task is not such simple analysis.
            The manufacturing team is able to produce the filter but only if you tell them how many layers
            is required and what the thickness and refractive index of each of them are. Furthermore, these
            refractive indexes must belong to the real materials in Table 8.4 or some extended one that
            makes the optical filter synthesis very challenging not only analytically but numerically too.
            According to (8.18)  and (8.19),  we have only three  independent  parameters for
            optimization:  ,  ,   and the problem of synthesis does not look difficult. However, the
                        
                               
                            
                        11
            number of layers might reach hundreds and that is a real problem. We can simplify the byline
            synthesis assuming that the electrical thickness of each layer is close to a quarter-wavelength,
            i.e.  ≅  ≅ /2, and thus the byline is the half-wavelength. Then each byline can play a
                
                     
            role of in-line resonator we have analyzed at the beginning of the current chapter. If so, such
            optical filter is the cascade of resonators with equal loaded Q-factor. That explains the fact that
            the transfer matrix of such filter is the transfer matrix of single byline aka resonator raised to
            power N. Recall the far-reaching analogy between the formation of the filter transfer function
            in the frequency domain and the development of radiation pattern of the linear antenna in space.
            At  the  heart of both phenomena is the EM  wave interference. In  Chapter 5  we  have
            demonstrated that a linear antenna uniformly excited has relatively high sidelobe level. The
            similar effect can be expected in filters with the same Q-factor, i.e. the excessive level of ripples
            in the stopband. Figure 8.4.16d on the next page confirms this fact perfectly well. The central
            wavelength of 10 bylines was chosen 1490 nm (green arrow). The passband characteristic is
            almost flat, but the peak oscillation in the stopband reaches -2dB. Nevertheless, such filters are
            simple in production and thus low-cost, as their fabrication requires a minimum set of dielectric
            materials (only two).
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