Page 40 - E-BOOK STOIKIOMETRI
P. 40
1
N OH 4 1
(a) Fraksi mol NaOH = = N OH: r = 1 = 1 ≈ 0,05
4 :5
g N OH 1 g 1
4
5
6
5
(b) Bpj = = = 10 atau bpj = 10 = 10
g rut n ,1 g 1
1
(c) Molalitas = N OH = 4 N COH = 2,8 mo / g
g H O , 9 g H O
3
(d) Karena massa jenis larutan = = 1 / dan persen massa = y% = 10%,
maka,
Molaritas = 1 ∙ ∙ = 1 ∙1 ∙1 = 2,5 mo /L
M m 4 g/
E-book Stoikiometri Berbasis Representasi Kimia 34
