Page 173 - Mechatronics with Experiments
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MECHANISMS FOR MOTION TRANSMISSION  159

                                      Mechanism          Input       Output
                                      characteristics    characteristics  characteristics
                         Mechanism type  n 1  η 1  J 1  T 1  S 2  2 J  T 2  S 1    J 1        T 1
                        Gear
                            1   r
                                1                                     θ 1 = n  θ 2
                                      2 r  ≤ 1.0  J r1  Tc.sgn(   )  θ  T           J           1
                                                                                r1   (         )
                                                      θ 1
                                 2    1 r                 2   2 J  2    2 r     J +  2 r2    i T +  nη  T  2
                                              J r2       +c  θ 1      = (     )  θ 2  n η
                                                                        1 r
                                r
                                2
                         Belt-Pulley          J                                   J r2 + J 2
                                  2            r1  Tc.sgn(   )        θ 1 = n  θ 2  J r1  +
                                      2 r  ≤ 1.0  J   θ 1                          n η       i T +  1  T
                                                                                    2
                                                                        2 r
                                                                                 W
                           1     r    1 r      r2    θ   θ 2  2 J  T  2  = (     )  θ 2  1  (           )  r 2  r 2  nη  2
                                                                                  belt
                                                                                  g
                          r       2           W  belt       +c 1        1 r  +                     (    +     )
                                                                                      1
                                                                                        2
                                                                               2
                          1
                         Ball screw or cam
                              2
                                 X
                                F                 Tc.sgn(   )
                                                      θ 1
                                  load        J                       θ 1 = n X  W     1       1
                                                                                   load
                                      π
                                                                                +
                                W  load  2  p  ≤ 1.0  lead  X  W  load  F load  J load   (          )   (         )  i T +  F  load
                                                                                   g
                                                     θ
                                                                                       2
                                                                        π
                                              W        +c 1           = (      ) X    n η      nη
                                                                       2  p
                         1                     load
                          θ π
                         X=  /2  p
                         Rack pinion                                              J pinion
                               p r  X
                         1                                                       W    1
                                 F                                                rack
                                  load                                         +    (         )    (         )
                                                                                      2
                                 W    1      J pinion  Tc.sgn(   )    θ 1 = n X   g  n η       1
                                                      θ 1
                                  load   ≤ 1.0           X  W    F                          i T +  F
                                      p r    W                load  load   1     W            n η  load
                                                                                               2
                                               rack
                                                                                      1
                                                                                  load
                                                       +c  θ 1        = (     ) X  +    (         )    (         )
                                                                        p r
                                                                                  g
                                                                                      2
                            2  X                                                     n η
                         Conveyor belt
                                 X
                                 F  load      J   Tc.sgn(   )                    J p1  +  J  p2
                        1        W load  1 p r  ≤ 1.0  p1  θ 1  X  W  F  θ 1 = n X          i T +  1  F load
                                                                               W
                                                                                belt W
                                                                         1
                                                                                       1
                                                                                 +
                                                                                               2
                                                                                   load
                           p r    2           J p2       +c  θ 1  load  load  = (     ) X     (                      )    (         )  n η
                                                                             +
                                                                                       2
                                              W                         p r      g     n η
                             p r               belt
                             FIGURE 3.15: Commonly used motion conversion (gear) mechanisms and their input–output
                             relationships.
                                4. Using the reflection equations developed above, calculate the reflected load inertia
                                  and torque/forces (J l,eff , T l,eff ) that will effectively act on the actuator shaft as well as
                                                                         ̇
                                                                   ̇
                                  the desired motion at the actuator shaft (   (t) =    (t)).
                                                                          in
                                                                   m
                                5. Guess an actuator/motor inertia from an available list (or make the first calculation
                                  with zero motor inertia assumption), and calculate the torque history, T (t), for the
                                                                                            m
                                  desired motion cycle. Then calculate the peak torque and RMS torque from T (t).
                                                                                                m
                                6. Check if the actuator meets the required performance in terms of peak and RMS
                                  torque, and maximum speed capacity (T , T rms ,    ̇ max ). If the above selected actua-
                                                                   p
                                  tor/motor from the available list does not meet the requirements (i.e., too small or too
                                  large), repeat the previous step by selecting a different motor.
                                                                                            ◦
                                7. The continuous torque rating of most electric servo motors is given for 25 C ambient
                                  temperature and an aluminum face mount for heat dissipation considerations. If the
                                                                          ◦
                                  nominal ambient temperature is different form 25 C, the continuous (RMS) torque
                                  capacity of the electric motor should be derated using the following equation for a
                                  temperature,
                                                                  √           ◦
                                                               ◦
                                                  T rms  = T rms (25 C) (155 − Temp C)∕130     (3.162)
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