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PROPERTIES OF ADDITION ON INTEGERS  EXAMPLE 14:    (i)    The successor of 19 is (19 + 1) = 20.
                              (ii)    The successor of -18 is (-18 + 1) = -17.
                              (iii)   The predecessor of 10 is (10 - 1) = 9.
 (i) CLOSURE PROPERTY OF ADDITION The sum of two integers is always an integer.           (iv)   The predecessor of -20 is (-20 - 1) = - 21.


 EXAMPLE 9:    (i)    3 + 5 = 8, and 8 is an integer.  EXAMPLE 15:   Find the sum of -8, 23, -32, -17 and -63.
          (ii)    3 + (-8) = - 5, and -5 is an integer.
          (iii)   (-3) + (-9) = -12, and -12 is an integer.  SOLUTION:    (-8) + 23 + (-32) + (-17) + (-63)
          (iv)   16 + (-7) = 9, and 9 is an integer.           = [(-8) + 23] + (-32) + [(-17) + (-63)]
                              = [15 + (-32) ] + (-80) = (-17) + (-80) = - 97.


 (ii) COMMUTATIVE LAW OF ADDITION if a and b are any two integers then a + b = b + a.  EXAMPLE 16:    Find an integer a such that
                              (i) 2 + a = 0  (ii) a + (-6) = 0
 EXAMPLE 10 :    (i)    (-3) + 8 = 5, and 8 + (-3) = 5.  SOLUTION:    (i) 2 + a = 0 => (-2) + [2 +a] = (-2) + 0 [adding (-2) on both sides]


 :. (-3)+ 8=8+(-3).           => [(-2) + 2] + a= - 2 [by associatlve law of additlon and property of 0]
                              => 0 + a= - 21·: (-2) + 2 = 0]
          (ii)    (-4) + (-6) = -10, and (-6) + (-4) = -10.  => a= -2.
                                     Hence, a = - 2.
 (iii) ASSOCIATIVE LAW OF ADDITION if a, b, care any three integers then(a + b) + c = a+ (b + c).
                              (ii)   a + (-6) = 0
 EXAMPLE 11:    Consider the integers -5, -7 and 3.           =>   [a + (-6) + 6 = 0 + 6 [adding 6 on both sides]
                              =>     a + [(-6) + 6] = 6 [by associative law of addition and property of O l
          We have: [(-5) + (-7) ) + 3 = (-12) + 3 = -9.            =>   a + 0 = 6   [·: (-6) + 6 = O]
          And, (-5) + 1(-7) + 31 = (-5) + (-4) = - 9.   =>  a = 6.
          :. [(-5) + (-7)) + 3 = (-5) + [(-7) + 3).
                              Hence, a = 6.
          (iv) if a is any integer then a + 0 = a and O + a = a.  SUBTRACTION OF INTEGERS


 EXAMPLE 12:   (i)  8 +  0 =  8     (ii) (-3) + 0  =  -3      (iii) 0 + (-5) = -5  We have learnt how to subtract two whole numbers.


 Remark      0 is called the additive identity.  We defined subtraction as an inverse process of addition. For example, to subtract 4 from 9 is the same as to find
        a number which when added to 4 gtves 9.
          (v) The sum of an integer and its opposite ts 0.
        Clearly, the answer is 5.
          Thus, if a ts an integer then a+ (-a)= 0.  Thus, 9 - 4 = 5.
          a and -a are called opposites or negatives or additive inverses of each other.
        We extend  the same idea to subtraction of integers. Suppose we want to subtract (-4) from 6.
 EXAMPLE 13:   3 + (-3) = 0 and (-3) + 3 = 0.  Clearly, we want a number which when added to (-4) gtves 6.
        Now, on the number line, find out how many steps should be taken from -4 to reach 6.
          Thus, the additive inverse of 3 is -3.
          And, the additive inverse of -3 is 3.
 Remark      Clearly, the additive inverse of 0 is 0.  -5  -4  -3  -2  -1  0  1  2  3  4       5      6

 SUCCESSOR AND PREDECESSOR OF AN INTEGER   We see that the number of steps taken is 10.
 Let a be an integer.      :. 6 - (-4) = 10.
    Then, (a+ 1) is called the successor of a.   Also, we know that 6 + 4 = 10.
    And, (a - 1) is called the predecessor of a.     Thus, 6 - (-4) = 6 + 4 = 10.
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