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EXAMPLE 20:           (i) 4 × (-7) = -28   (ii) 7 × (-4) = - 28
 RULE  To subtract one integer from another, we take the additive inverse of the integer to be            (iii) (-9) × 4 = -36   (iv) (-3) × 7 = - 21
       subtracted and add it to the other integer.
       Thus, if a and bare two integers then a -b =a+ (-b).  RULE 2:To find the product of two integers with the same sign, we find the product of their values regard
        less of their signs and give a plus sign to the product.
 SOLVED EXAMPLES
        EXAMPLE 21:           (i) 4 × 13 = 52      (ii) (-4) × (-13) = 52
 EXAMPLE 17: Subtract           (iii) (-7) × (-9) = 63  (iv) (-18) × (-10) = 180
          (i) 7 from 2   (ii) -8from 5  (iii) 4from -9  (iv)-7 from -5
        EXAMPLE 22: Find each of the following products:
 SOLUTION:    (i)   2 - 7 = 2 + (negative of 7) = 2 + (-7) = -5.           (i) 36 × (-17)     (ii) (-81) × 15
          (ii)   5 - (- 8) = 5 + (negative of -8) = 5 + 8 = 13.           (iii) (-23) × (-18)   (iv) (-60) × (-21)
 .         (iii)   - 9 - 4 = - 9 + (negative of 4) = (-9) + (-4) = -13.
          (iv)   - 5 -(-7) = (-5) + (negative of -7) = (-5) + 7 = 2.  SOLUTION:    (i)   36 × (-17) = -(36 × 17) = -612.
                              (ii)   (-81) × 15 = -(81 × 15) = -1215.
 EXAMPLE 18:  Subtract           (iii)   (-23) × (-18) = 23 × 18 = 414.
          (i) - 2459 from 5128  (ii) -1040 from - 687           (iv)   (-60) × (-21) = 60 × 21 = 1260.
          (iii) 347 from - 58   (iv) -728 from 0
 SOLUTION:    We have:           PROPERTIES OF MULTIPLICATION ON INTEGERS
          (i)   5128 - (-2459) = 5128 + 2459 = 7587 [negative of -2459 is 2459)
          (ii)   -687 - (-1040) = - 687 + 1040 = 353 [negative of -1040 is 1040]  (ii) COMMUTATIVE LAW FOR MULTIPLICATION For any two integers a and b, we have a × b =b × a.
          (iii)    -58 - (347) = (-58) + (-347) = - 405 [negative of 347 is -347]
          (iv)    0 - (-728) = 0 + 728 = 728 [negative of -728 is 728]  EXAMPLE 24:   (i) 3 × (-7) = - 21, and (-7) × 3 = - 21.

 EXAMPLE 19: The sum of two integers is -27. if one of them is 260,flnd the other.           :. 3 × (-7) = (-7) × 3.


 SOLUTION:  Let the other number be x . Then,           (ii) (-5) × (-8) = 40, and (-8) × (-5) = 40.

          260 + × = (-27)            :.  (-5) × (-8) = (-8) × (-5).
           =  × = (-27) - 260 = (-27) + (-260) = - 287.
          Hence, the other number is -287.  (iii) ASSOCIATIVE LAW FOR MULTIPLICATION if a, b, c are any three integers then
               (a × b) × c = a × (b × c).
 PROPERTIES OF SUBTRACTION ON INTEGERS
        EXAMPLE 25:           Consider three integers (-7), (-5) and (- 8).
 (i) CLOSURE PROPERTY if a and b are integers then (a - b) is also an integer.           We have: 1(-7) × (-5)) × (-8) = 35 × (-8) = - 280.
 (ii) If a is any integer then (a - 0) = a.           And, (-7) × 1(-5) × (-8)) = (-7) × 40 = - 280.
 (iii) If a, b, care integers and a > b then (a - c) > (b - c).           :. [(-7) × (-5)) × (-8) = (-7) × [(-5) × (-8)).

        EXAMPLE 26:           Consider three integers 3, (-5) and (-7).
 MULTIPLICATION OF INTEGERS           We have: [3 × (-5)) x (-7) = (-15) × (-7) = 105.
                              And, 3 × [(-5) × (-7)) = 3 × 35 = 105.
 RULE 1 To find the product of two integers with unlike signs, we find the product of their values regardless of    13 × (-5) × (-7) = 3 × [(-5) × (-7)].
 their signs and give a minus sign to the product.
        (iv) DISTRIBUTIVE LAW if a, b, c be any three integers then a × (b + c) = a × b + a × c.
          (i) 4 × (-7) = - 28      (ii) 7 × (-4) = - 28
          (iii) (-9) × 4 = -36      (iv) (-3) × 7 = - 21  EXAMPLE 27:   Consider the integers 4, (-5) and (-6).
                              We have: 4 × 1(-5) + (-6) = 4 × (-11) = - 44.
 RULE 2 To find the product of two integers with the same sign, we find the product of their values regard            And, 4 × (-5) + 4 x (-6) = (-20) + (-24) = - 44.
 less of their signs and give a plus sign to the product.            4 × 1(-5) + (-6)) = 4 × (-5) + 4 × (-6).
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