Page 32 - TUTORIAL MATEMATIKA IPS KELAS XI-2
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TURUNAN FUNGSI ALJABAR

                        2
                                              2
            58.     +    = 75  →    = 75 −   
                                     2
                                                     3
                     =      = (75 −    )   = 75   −   
                      ′
                                                2
                                   2
                  →    = 75 − 3   = 3(25 −    ) = 3(5 −   )(5 +   )
                      ′
                  ∴    = 0  →    = −5 ,    = 5

                  -------------   ++++++++++  -------------
                                   -5                      5
                  Mencapai maksimum pada    = 5  →    = 50  →               = 50.5 = 250

            59.         = 36
                      
                                     2
                               ′
                                                 2
                        3
                     =     →    = 3   →        = 3  
                                             
                              
                                2
                  →     .  = 3  
                              
                                2
                  → 36 .   = 3  
                             
                           1  2
                  →    =      
                           12
                           12
                  →    =    … (  )
                              2
                         2
                                            2
                                      2
                     = 6    → 24 = 6   →    = 4 … (    )
                                        12          
                  Dari (i) dan (ii) :   =   = 3
                                        4                

                        2
            60.     =    .   
                                                               2
                         2
                                             2
                     = 2   + 4      → 96 =  2   + 4      → 48 =    + 2      →    =  48−   2
                                                                                2  
                                      2
                                                 1
                                                    3
                                2
                        2
                     =    .    =    .  48−    = 24   −    
                                   2             2
                             3
                                                       3
                                               3
                                                         2
                    ′
                                                                     2
                                                 2
                                2
                     = 24 −    → 0 =  24 −     →     = 24  →    = 16  →    = 4 (sisi tidak boleh -)
                             2                 2       2
                                48−4 2  32               2            3
                     = 4  →    =      =    = 4  →    = 4 . 4 = 64     
                                  2.4    8

            61.
                                B



                                O                        A
                  Persamaan garis g:      +      =     
                  ∴ (4, 3) → 4   + 3   =     
                                                                4  
                  → 4   =      − 3    → 4   =   (   − 3) →    =
                                                                 −3
                          1      1       1 4         2   2
                  →    =       =       =      .    =
                          2      2   2   2   −3        −3
                                             2
                                                     ′
                      ′
                                                                 2
                  →    =   4  (  −3)−2   .1  =   2   −12    ;    = 0  →  2   − 12   = 0
                              (  −3) 2     (  −3) 2
                  2  (   − 6) = 0  →    = 0 ,    = 6 karena sisi harus > 0 maka nilai B yang memenuhi adalah 6
                          4.6
                                      ̅̅̅̅
                                               2
                                                                 2
                                                            2
                                                     2
                  →    =      = 8  →      = √   +    = √8 + 6 = 10
                          6−3
                                                                                      ‘LEARNING IS FUN’  31
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