Page 190 - MUDAH DAN AKTIF BELAJAR FISIKA SMA KELAS X
P. 190
)4;08= 30?0B 38ACAC= A420@0 A4@8 30= ?0@0;4; :><?>=4= :><?>=4=
;8AB@8: 30?0B ?C;0 38ACAC= A420@0 601C=60= A4@8 ?0@0;4;
Mari Mencari Tahu Tantangan
untuk Anda
&4@70B8:0= 60<10@ 14@8:CB
41C07 @0=6:080= B4@BCBC? F0=6 B4@38@8 0B0A 3C0 1C07 @4A8AB>@ 30= A41C07 AC<14@ Jika Anda telah memahami susunan
B460=60= seri hambatan pada rangkaian,
tentukan oleh Anda sehingga
diperoleh persamaan (8 – 12),
I 1 R 1 persamaan (8 –13), dan persamaan
(8 – 14) dengan cara menurunkan
R 2
I 2 dari persamaan (8 – 9) dan
I I
persamaan (8 – 10).
V
*C60A =30 030;07 <4<1C:B8:0= ?4@A0<00= ?4@A0<00= 14@8:CB &4@A0<00=
?4@A0<00= 14@8:CB 14@6C=0 C=BC: <4=F434@70=0:0= 30= <4<?4@<C307
?4=F4;4A080=
8:0 B4@30?0B 70<10B0= 38ACAC= ?0@0;4; 14@;0:C
I I 2-2
2-2
I 2-2
+=BC: , 1C07 70<10B0= F0=6 38ACAC= ?0@0;4; 30= A4B80? 70<10B0= 14A0@=F0
70<10B0= B>B0;=F0 030;07
,
+
0<10B0= ?0@0;4; 14@5C=6A8 A410608 ?4<1068 0@CA 34=60= =8;08 ?4@10=38=60=
:C0B 0@CA ?030 A4B80? 2010=6 030;07
G
2-2 R 1 R 2
430 ?>B4=A80; A4B80? 70<10B0= A0<0 14A0@ 2-2 P R
G
4. Jembatan Wheatstone R 4 R 3
S
4<10B0= 212-,# <4@C?0:0= A41C07 <4B>34 F0=6 386C=0:0= C=BC: V
<4=6C:C@ 70<10B0= F0=6 14;C< 38:4B07C8 )4;08= 8BC 94<10B0= 4 212-,#
386C=0:0= C=BC: <4=6>@4:A8 :4A0;070= F0=6 30?0B B4@9038 30;0< Gambar 8.12
Rangkaian jembatan Wheatstone
?4=6C:C@0= 70<10B0= <4=66C=0:0= C:C< %7< )CAC=0= @0=6:080=
94<10B0= -740BAB>=4 38BC=9C::0= ?030 #.$#2
8:0 90@C< 60;D0=><4B4@ <4=C=9C::0= 0=6:0 =>; A4B8<10=6 14@
0@B8 ?030 60;D0=><4B4@ B830: 030 0@CA ;8AB@8: F0=6 <4=60;8@ :810B=F0 R R X
?030 :40300= 8=8 B460=60= 38 A0<0 34=60= B460=60= 38
30= B460=60= 38 A0<0 34=60= 38 A478=660 98:0 G
14@;0:C
L L K
1 2
&23#.##/ 9 38:4=0; 34=60= ?@8=A8? 94<10B0= -740BAB>=4 E S
4=BC: A434@70=0 A41C07 94<10B0= -740BAB>=4 38BC=9C::0= A4?4@B8 Gambar 8.13
Rangkaian sederhana jembatan
?030 #.$#2 !4B8:0 A0:;0@ 387C1C=6:0= 0@CA <4=60;8@ <4;0;C8 Wheatstone
Listrik Dinamis 181