Page 65 - E-BOOK INTERAKTIF BERORIENTASI EVERYDAY LIFE PHENOMENA PADA MATERI ASAM BASA
P. 65
Kolom Komentar
-
HA(aq) H (aq) + A (aq)
+
Mula-mula : ………… b mol 0 0
Terionisasi: -…………b mol +…………b mo +…………b mol
Sisa : …………b-b mo…………l …………b mol b mol
b………… ( 1- ) mol
b(1−α) mol
-
+
[HA] = [H ] = [A ] =
V L
Kolom Jawaban
-
HA(aq) H (aq) + A (aq)
+
Mula-mula : b mol 0 0
Terionisasi: -b mol +b mol +b mol
Sisa : b-b mol b mol b mol
b(1- ) mol
-
+
[HA] = b(1−α) mol [H ] = [A ] = bα mol
V L V L
Tuliskan tetapan kesetimbangan HA, lalu substitusi [HA] = b(1−α) mol dan
V L
[H ] = [A ] = bα mol ke persamaan Ka dari HA!
-
+
V L
Kolom Komentar Kolom Jawaban
−
+
−
+
[H ] [A ] [H ] [A ]
Ka = Ka =
[HA] [HA]
bα mol x bα mol bα mol x bα mol
Ka = V L V L Ka = V L V L
b(1−α) mol b(1−α) mol
V L V L
bα mol x bα mol bα mol x bα mol
Ka = V L V L Ka = V L V L
b(1−α) mol b(1−α) mol
V L V L
bα mol x α bα mol
Ka = V L Ka = V L x α
(1−α) (1−α)
b mol x 2 b mol 2
Ka = V L Ka = V L x
(1−α) (1−α)
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