Page 45 - PC 101 practical notes 24-25..
P. 45

MANSOURA NATIONAL UNIVERSIY
         PHARM D- CLINICAL PHARMACY                        LEVEL I                        PHARM. ANAL. CHEM. I (PC 101)



           For Na 2CO 3 :

                                     Na 2CO 3 + 2HCl → 2NaCl + CO 2 + H 2O

                                                 2 HCl ≡ 1 Na 2CO 3

                                               standard       sample

                                                             1
                                                1 HCl ≡   Na 2CO 3
                                                             2
                                                  standard         sample
          Equivalence factor (F):
                                               1   x M.W. of Na 2CO 3 x 0.2

              each ml of 0.2 N HCl ≡           2                                    ≡ ..........  g Na 2CO 3
                                                          1 x 1000


          Concentration:

                                            2(E.P 2 - E.P 1) x F x 1000
               Concn. of Na 2CO 3 =                                           = ..........  g/L
                                                          10
          Results:


             E.P 1 =


             E.P 2 =


             Concn. of NaOH =

             Concn. of Na 2CO 3 =






                Explanation









              Demonstration


                    of the

                experiment







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