Page 11 - Modul SPLTV

Langkah 4: substitusik nilai z = 72 (6), :
11
⟹ −33y + 54Z = − 63

72
⟹ −33y + 54 ( ) = − 63
11
3.888
⟹ −33y + = − 63
11
⟹ 363 + 3.888 = − 63
11 11
363 3.888
⟹ = − 63 −
11 11
363 693 3.888
⟹ = − −
11 11 11

363 4.581
⟹ = −
11 11
−4.581
11
⟹ =
363
11
4.581 11
⟹ = ×
11 363
4.581
⟹ =
363
4.581 72
Langkah 5: substitusi = dan Z = ke persamaan (7), menjadi:
363 11
9 −3 + 4
=
2
4.581 72
9 − 3( ) + 4 ( )
= 363 11
2
4.581 72
9 − 3( ) + 4 ( )
= 363 11
2
13.743 288
9 − +
= 363 11
2
3.267 13.743 9.504
363 − 363 + 363
=
2
− 972
363
=
2
363
= x 2
−972