Page 120 - Pengembangan E-Modul Berbasis STEAM Pada Materi Asam Basa_Nur Sirril Hayat

7. Dik :

M = 0,2 M = √2 × 10 . 2 × 10
−1
−5
Ka = 2 x 10 = √4 × 10
-5
−6
Dit : = 2 x10
-3
pH? pH = - log [H ]
+
Jawab: = - log 2 x10
-3
[H ] = √ . = 3-log 2
+

Jawaban : A

8. Dik :

M = 0,1 M [OH ] = 10 -3
-
pH = 11 [OH ] = √ .
-

Dit : 10 -3 =√ . 10
−1

Kb? (10 ) = Kb . 10
-3 2
−1
Jawab: 10 = Kb . 10
−6
−1
pOH = 14-11
10 −6

= 3 10 −1 =
−5
pOH = -log 10 -3 = 10

Jawaban : C

9. Dik :

pH = 3

Dit :

[ ]?
−
Jawab:

pOH = 14-3

= 11

pOH = -log 10 -11

[ ] = 10 -11
−
Jawaban : D

E-MODUL ASAM BASA BERBASIS STEAM 108