Page 122 - Pengembangan E-Modul Berbasis STEAM Pada Materi Asam Basa_Nur Sirril Hayat

= 12,3
Skor Maksimal 20

No Kunci Jawaban Skor
3. Dik : Dit :
M = 0,02 M pH ... ? 4
b = 1
Jawab 4
[OH ] = b x M
-
= 1 x 0,02
= 0,02 4
= 2 x 10 -2
pOH = -log [OH ]
-
= -log 2 x 10 -2 4
= 2 –log 2
pH = 14 – (2 –log 2)
= 12 + log 2 4
= 12,3
Skor Maksimal 20

No Kunci Jawaban Skor
4. Dik : Dit :
M = 0,01 M pH ... ? 4
Kb = 10 -4
Jawab 4
[OH ] = √ ×
-

= √10 −4 × 10
−2
= √10 4
−6
= 10 -3
pOH = -log 10 -3 4
= 3
pH = 14 – 3 4
= 11
Skor Maksimal 20

No Kunci Jawaban Skor
5. 4
pH = 10 + log 2
pOH = 4 – log 2 4
= -log 2 x 10 -4
[OH ] = 2 x log 4
-
-4
[OH ] = √ .
-

2 x 10 = √5 × 10 . 4
-4
−5
4 x 10 = 5 x 10 . M
-5
-8
M = 4 ×10 −8
5×10 −5 4
= 8 x 10 -4
Skor Maksimal 20

E-MODUL ASAM BASA BERBASIS STEAM 110