Page 7 - E-Modul Turunan Fungsi Aljabar
P. 7
′( ) = ( + h) − ( )
lim
h→0 h
3
2
2
3
= + 3 ℎ+3 ℎ + ℎ + 9 − ( + 9)
3
lim
h→0 h
2
2
= 3 ℎ+3 ℎ + ℎ 3
lim
h→0 h
= ℎ(3 + 3 ℎ + ℎ )
2
2
lim
h→0 h
= lim(3 + 3 ℎ + ℎ )
2
2
h→0
2
= 3 + 3 . 0 + 0
2
2
= 3 + 0 + 0
= 3
2
3
d. ( ) =
( + ℎ) = 3
+ ℎ
′( ) = ( + h) − ( )
lim
h→0 h
= 3 − 3
+ ℎ
lim
h→0 h
= 3 − 3( + ℎ)
( + ℎ)
lim
h→0 h
= 3 − 3 − 3ℎ
lim
h→0 hx(x + h)
= −3ℎ
lim
h→0 hx(x + h)
= −3
lim
h→0 x(x + h)
= −3
lim
2
h→0 + xh
= −3
2
+ 0
6 | T u r u n a n K e l a s X I S M A
