Page 11 - E-Modul Turunan Fungsi Aljabar

Penyelesaian

2
3
a. ( ) = − − 7
3
2
′
Misal: = − → = −3 3−1 = −3
1
2
′
= 7 → = 7.2. 2−1 = 14 = 14
′
′
Jadi jika ( ) = − , maka ( ) = − = −3 − 14
′
2
2
b. ( ) = 4 + 15
′
2
Misal: = 4 → = 4.2. 2−1 = 8
0
= 15 → = 15. 1−1 = 15. = 15
′
Jadi jika ( ) = + , maka ( ) = + = 8 + 15
′
′
′
3
c. ( ) = 9 − 3 + 5
2
′
3
2
Misal: = 9 → = 9.3. 3−1 = 27
′
′
= 3 → = 3. 1−1 = 3
′
′
= 5 = 5 −2 → = 5. (−2). −2−1 = −10 −3 = −10
2 −3
′
Jadi, jika ( ) = − + , maka ( ) = − +
′
′
′
10
′
2
( ) = 27 − 3 −
−3
3
d. ( ) = 5 − √ + 1
2
0
′
Misal: = 5 → = 5. 1−1 = 5 = 5
2
2 2 −1 2 − 1 2
3
= √ = 3 → = 3 = 3 = 3
′
2
3 3 3 √
′
= 1 → = 0
′
′
Jadi, jika ( ) = − + , maka ( ) = − + ′
′
′
( ) = 5 − 2
3
3 √

10 | T u r u n a n K e l a s X I S M A