Page 175 - Linear Models for the Prediction of Animal Breeding Values 3rd Edition
P. 175

Marker inheritance
              Calf    Sex of calf  Sire    Dam     Sire    Dam     PWG (kg)

              1       Male          –        –      –        –        6.8
              2       Female        –        –      –        –        4.5
              3       Male          1        2     M  p     M  m      8.5
                                                     1        2
              4       Female        1        3     M  m      M  p     6.0
                                                     1        3
              5       Female        4        3     M  p      M  p     7.0
                                                     4        3
                                         p
                                               m
            For ease of illustration, let rows i  and i  for animal o in G  be coded as ip and
                                         o     o                v
                                                   p
                                                        m
        im, respectively. Thus, for example, for animal 1, i  and i   will be coded as 1p and 1m,
                                                   1    1
                                p
                                      m
        respectively, for animal 2, i  and i  will be coded as 2p and 2m and for animal 5, i p
                                2     2                                          5
             m
        and i  will be coded as 5p and 5m, respectively. The G  for the example, therefore, is:
             5                                         v
               1p     1m     2p     2m     3p     3m     4p     4m     5p     5m
        1p    1.000  0.000  0.000  0.000  0.900  0.000  0.100  0.810  0.171  0.810
        1m    0.000  1.000  0.000  0.000  0.100  0.000  0.900  0.090  0.819  0.090
        2p    0.000  0.000  1.000  0.000  0.000  0.100  0.000  0.010  0.001  0.010
        2m    0.000  0.000  0.000  1.000  0.000  0.900  0.000  0.090  0.009  0.090
        3p    0.900  0.100  0.000  0.000  1.000  0.000  0.180  0.900  0.252  0.900
        3m    0.000  0.000  0.100  0.900  0.000  1.000  0.000  0.100  0.010  0.100
        4p    0.100  0.900  0.000  0.000  0.180  0.000  1.000  0.162  0.916  0.162
        4m    0.810  0.090  0.010  0.090  0.900  0.100  0.162  1.000  0.246  0.820
        5p    0.171  0.819  0.001  0.009  0.252  0.010  0.916  0.246  1.000  0.228
        5m    0.810  0.090  0.010  0.090  0.900  0.100  0.162  0.820  0.228  1.000
            The calculation of G  for the first three animals is illustrated as below. For the
                              v
        first two animals, the parents are unknown, therefore:
            g    = g     = g   = g    = 0
             1p,1p  1m,1m  2p,2p  2m,2m
                                      p
        At the ML, animal 3 inherited M  from his father; therefore, for row 3p in G , cor-
                                     s                                      v
        responding to the effects of the paternal alleles of the MTQL for animal 3, r = 0.1.
        Hence, from Eqn 10.7:
            g     = (1 − 0.1)g   + (0.1)g   = (0.9)1 + (0.1)0 = 0.9
             3p,1p          1p,1p     1m,1p
            g     = (1 − 0.1)g   + (0.1)g   = (0.9)0 + (0.1)1 = 0.1
             3p,1m          1p,1m      1m,1m
            g     = (1 − 0.1)g   + (0.1)g   = (0.9)0 + (0.1)0 = 0
             3p,2p          1p,2p     1m,2p
            g     = (1 − 0.1)g   + (0.1)g   = (0.9)0 + (0.1)0 = 0
             3p,2m          1p,2m      1m,2m
            g     = 1.0
             3p,3p
                                    m
        At the ML, animal 3 inherited M  from his mother; therefore, for row 3m in G , corres-
                                    d                                     v
        ponding to the effects of the maternal alleles of the MTQL for animal 3, r = 0.9.
        Hence, from Eqn 10.8:
            g     = (1 − 0.9)g   + (0.9)g   = (0.1)0 + (0.9)0 = 0
             3m,1p         2p,1p      2m,1p
            g     = (1 − 0.9)g   + (0.9)g   = (0.1)0 + (0.9)0 = 0
             3m,1m          2p,1m      2m,1m
            g     = (1 − 0.9)g   + (0.9)g   = (0.1)1 + (0.9)0 = 0.1
             3m,2p          2p,2p      2m,2p
        Use of Genetic Markers in Breeding Value Prediction                  159
   170   171   172   173   174   175   176   177   178   179   180