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3. f(x) = x2 + 2x - 3.
a. Hitunglah f(–4), f(–3), f(-2), f(-1), f(0), dan f(2)
f(–4) = (-4)2 + 2(-4) – 3 = 5
f(–3) = (-3)2 + 2(-3) – 3 = 0
f(-2) = (-2)2 + 2(-2) – 3 = -3
f(-1) = (-1)2 + 2(-1) – 3 = -4
f(0) = (0)2 + 2(0) – 3 = -3
f(1) = (1)2 + 2(1) – 3 = 0
f(2) = (2)2 + 2(2) – 3 = 5
b.
c. D = {x||–4 ≤ x ≤ 2, x∈ R}
f
R = {y||–4 ≤ y ≤ 5, y∈ R}
f
