Page 52 - E-MODUL Fungsi komposisi dan fungsi invers

Cara 2

(g o h) (x) = g (h(x))

= g (2x – 7)

= (2x – 7)−6
2(2x – 7)

= 2x −13
4x – 14
Misalkan (g o h) (x) = y maka,

y = 2x −13
4x – 14
y ( 4x – 14) = 2x – 13

4xy – 14y = 2x – 13

4xy – 2x = 14y – 13

x (4y – 2) = 14y – 13

x = 14y – 13
4y – 2

-1
(g o h) (x) = 14x – 13
4x – 2
(h o g) (x) = h (g(x))

= h ( −6 )
2
= 2 ( −6 ) – 7
2
= 2 −12 – 7
2
= 2 −12−14
2
= −12 −12
2
= −12 ( +1)
2

= −6 ( +1)

Modul Elektronik Menggunakan Pendekatan Kontekstual | 44