Page 32 - E-Modul Fluida Dinamis

Contoh Soal

Penyelesaian:
a. = .
2 2 2
1 1 3
2
2
= . 2 = (3,14)(0,075) . 2 = 0,008836 = 8,836 /
4
4

= = 8,836 /
2
1
b. . = 8,836 /
1 1
8,836 . 10 −3 8,836 . 10 −3 8,836 . 10 −3
= 1 = 1 = 1,963 . 10 −3 = 4,5 /
1
4 (0,05) 2 4 (3,14)(0,0025)

c. = +
3
2
4
= + 0,5 = 1,5
2 3 3 3
2 0,008836 = 0,00589 /
3
3
= 1,5 = 1,5

= 3
3 3
0,00589
=
1,5
2
= 0,003927

d. = √1 = √ 4.0,003927 = √ 0,015708 = √0,00500254777 = 0,071 m
3
3 4 3,14 3,14

4
4
4
e. = .
1
2 = .
4
4
3

1 . = .
2 3 3 4 4
1
2 . 1,5.0,003927 0,00294525 = 4,17 /
4
= 1 (3,14)(0,03) 2 = 0,0007065
4

Dengan Pendekatan STEM 27