Page 116 - Distribusi peluang binomial
P. 116
x = 1 x = 3 1
f x = x + 2
C 20
L P(X < 3) = P(1 < X < 3)
3
1
D න X + 2 = L
20 AKLD
1
A K B
AK = 3 − 1 = 2
1 3 1 5
AD = f 1 = 20 1 + 2 = 20 KL = f 3 = 20 3 + 2 = 20
