Page 118 - Distribusi peluang binomial

A D P(X < 3) = P(1 < X < 3)

3
1

න X + 2 = L
20 AKLD

K L 1 1

= KL + AD AK
2

1 5 1 3 5

= 20 3 + 2 = 20 = 2 20 + 20 (3 − 1)

1 3

= 20 1 + 2 = 20 = 1 8 (2)

AK = 3 − 1 = 2 2 20

2

=
5