Page 117 - Distribusi peluang binomial
P. 117
A D P(X < 3) = P(1 < X < 3)
3
1
න X + 2 = L
20 AKLD
K L 1 1
= KL + AD AK
2
1 5 1 3 5
= 20 3 + 2 = 20 = 2 20 + 20 (3 − 1)
1 3
= 20 1 + 2 = 20 = 1 8 (2)
AK = 3 − 1 = 2 2 20
2
=
5
