Page 291 - Area 9 - Relevant Document

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200 kg/ha 5.1 4.2 4.8 4.3 18.4 4.60
G R A N D T O T A L 71.6

STEP 1. After grouping the data into treatments and replications,
compute the CF and TSS the same as the CRD with unequal number of
replications. THUS:

a. CF = (GT) = (71.6)
2
2
rt 4(5)

2
= (71.6) = (5126.56) = 256.33
20 20

b. TSS = X - CF
2
= (2.02 + (1.6) + (1.5) ……………..+((4.3) - 256.33
2
2
2
= 283.36 - 256.33 = 27.03
STEP 2. Determine the df(degrees of freedom) for the various SVs
(sources of variations)

Tdf = rt - 1

= 4(5) - 1 = 20 - 1 =19

tdf = t - 1

= 5 – 1 = 4

Edf = Tdf –tdf = 19 -4 = 15

STEP 3.Compute the tSS and the ESS

For tSS, since the number of replications is equal for all treatments, the
divisor ( r ) to be used should be common to all the squares of treatment totals.
Thus, the computation will be:

tSS = (tT) - CF
2
r
= (6.3) + (13.2) + (15.5) + (18.2) +(18.4) - 257.76
2
2
2
2
2
4